example of an electrophilic aromatic substitution reaction‚ in which a proton of an aromatic ring is replaced by a nitro group. Many aromatic substitution reactions are known to occur when an aromatic substrate is allowed to react with a suitable electrophilic reagent‚ and many other groups besides nitro may be introduced into the ring. Although the reaction produced a low yield at the end‚ the yield is calculated from the reaction and limiting reagent. Keywords: electrophilic aromatic substitution
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Nitration of Methyl Benzoate Purpose: The purpose of this experiment was to synthesize methyl m-Nitrobenzoate from methyl benzoate‚ concentrated HNO3‚ and concentrated H2 SO4 by an electrophilic substitution reaction. The H2 SO4 and the HNO3 were initially combined to form nitronium ion which was then used as an electrophile in the reaction. Crystals that were collected after the formation of the methyl m-Nitrobenzoate were collected by vacuum filtration and the product was isolated and purified
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as follows: Nitration test (negative)‚ Bromine test (positive) and Basic Oxidation test (positive). From these results the unknown sample can be classified as non-aromatic and unsaturated. INTRODUCTION Hydrocarbons are organic compounds that consist of only C and H atoms. They include the alkanes‚ alkenes‚ alkynes‚ and aromatic hydrocarbons. Because of their relatively non-polarity‚ all hydrocarbons are insoluble in water. When hydrocarbons burn in sufficient oxygen‚ carbon dioxide and water
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TLC and spectral data that determined most products were pure while some had a few impurities indicated by GC‚ LC‚ and a wide melting point range was shown for products 2 and 3. The presence of water in product 2 and 7 was indicated by the IR. Acetanilide and diazoaminobenzene had good yields compared to the other products with low-moderate yields. Introduction: The purpose of this lab is to develop problem solving skills needed to scale synthetic procedures for five products derived from aniline
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Time Corrected Ret. Time 1 0.720 0 2 1.088 0.368 Chloride: 9.0 mL Petroleum Ether: 3 mL Diethyl Carbonate: 0.250mL Methyl Benzoate: 0.250mL Table 4: GC 2
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group increases. e) i.e.‚ Benzoic acid is stronger than acetic acid. Reason : due to –I effect of phenyl group. Relative basic strength of amines 1. All aliphatic amines are more basic than ammonia. e.g. Methyl amine is more basic than ammonia. Reason : Due to +I effect of methyl group. 2. Aniline is weaker base than Ammonia. Reason : Due to
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Triphenylmethanol Aim The aim of this experiment was to prepared Grignard reagent (phenylmagnesium bromide) from bromobenzene and magnesium‚ to use the reagent prepared to synthesise a tertiary alcohol (triphenylmethanol) by reacting reagent and ester (methyl benzoate)‚ and the product formed is analyse by infrared spectroscopy (IR)‚ melting point‚ thin layer chromatography (TLC)‚ gas chromatography mass spectrum (GCMS) and finally Nuclear Magnetic Resonance spectroscopy. Introduction Formation of long hydrocarbon
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aniline‚ phenol‚ anisole and acetanilide after reacting with pyridinum tribromide in order to undergo electrophilic aromatic substitution. The melting point of the isolated products were measured against the standards in order to determine how strong of an ortho/para activator the compound was based on the product(s) and melting point obtained. Theory: Electrophilic aromatic substitution is an organic reaction that takes place when an atom that is bound to an aromatic ring is replaced by an electrophile
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hexagonal ring of carbon called as benzene in their molecule. Aromatic hydrocarbon can contain one or more than one benzene ring. Those compounds which contain more than one benzene ring are known as polynuclear aromatic hydrocarbon like naphthalene‚ anthracene etc. The aromatic compounds are generally taken as derivatives of benzene. Benzene and its derivatives are mainly used in synthetic organic chemistry. The main source of polynuclear aromatic compounds is coal tar. For example‚ naphthalene is the
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(3)NMRQuestion 1 1 / 1 point Equivalent protons in a molecule will result in one NMR signal. How many NMR signals would you predict for each of the following molecules? __1__ benzene __2__ 3-pentanone __4__ toluene __3__ ethanol __2__ t-butyl methyl ether 1. 1 2. 2 3. 3 4. 4 Question 2 1 / 1 point A compound to be analyzed by NMR should be dissolved in a solvent. Clearly the solvent should not have an NMR signal in the spectral area you are trying to analyze. Which solvents are appropriate
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