1 PRACTICE EXAM (not all questions pertain to a specific mid-term). This is taken from an earlier final exam. 1. (4 pts) Permanganate ion oxidizes sulfide ion to elemental sulfur (which you should represent as a single S atom) and is reduced to MnO2 in basic solution. In the balanced equation for this reaction‚ which you should determine in the work area‚ how many water molecules and hydroxide ions are needed in the final balanced equation? Work area: # of H2O ____4______ # of OH-
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notice the trans-alkenes in small rings. 60 Chemistry S-20 Week 1 Carbocation Stability 1. Draw the structure of the methyl cation‚ CH3+. Describe the hybridization‚ geometry‚ and orbitals in this species. H H H Carbon is sp2-hybridized‚ with 120° bond angles and a vacant p-orbital. 2. Each of the following carbocations is significantly more stable than
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Study material CHEMISTRY CLASS: XII KENDRIYA VIDYALAYA SANGATHAN LUCKNOW R E G I O N 2009-2010 Study Material Class XII -Chemistry SHRI RANGLAL JAMUDA IAS‚COMMISSIONER CHIEF Patron KENDRIYA VIDYALAYA SANGTHAN NEW DEHLI SHRI M.S Chauhan Asst. Commissioner Patron Kendriya Vidyalaya Sangthan Lucknow Region SHRI S.S. Rawat Guidance Smt. A.N Siddiqui (Education officer) (Education officer) SHrI K.‚M. Bhatnagar (Education officer) Co-ordinator SHRI. T. Singh Principal K.V. No. 2
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Organic Chemistry Basic Ideas: Carbon chains: Straight chains and branched chains‚ Numbering of chains and branches. Carbon Rings: Cyclic Molecules‚ Aromatic Compounds Types of Organic reactions: Combustion Addition Substitution Condensation Oxidation What is organic chemistry? Carbon compounds. Methane CH4 Hexane C6 H14 Ethane C2H 6 Heptane C7 H16 Propane C3H 8 Octane C8 H18 Butane C4H10 Nonane C9H20 Pentane C 5 H12 Decane C1 0 H22 Alkanes: Saturated Hydrocarbons
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another molecule. The double bond between the carbon atoms is weaker because the type of orbital is ‚ compared to a bond between the single-bonded carbon atoms. The reason that the orbital is weaker is because of the way that the electrons orbit the atoms‚ which is in an hour glass formation. This means that the area that the electrons overlap is above and below the two bonded atoms. Comparatively‚ the area of overlap between two bonded atoms with a sigma bond is between the two atoms (see figure 2).
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SYLLABUS FOR ENTRANCE TEST 2012 UNIVERSITY OF HEALTH SCIENCES LAHORE‚ PAKISTAN STRUCTURE OF ENTRANCE TEST PAPER 2012 Sr.# Subject No. of Questions 1. PHYSICS 44 2. CHEMISTRY 58 3. ENGLISH 30 4. BIOLOGY 88 TOTAL 220 CONTENTS PHYSICS Syllabus TOS Self Test Questions CHEMISTRY Syllabus TOS Self Test Questions ENGLISH Syllabus Self Test Questions BIOLOGY Syllabus TOS Self Test Questions PAGE# 1-5 6 7-9 10-21 22 23-28 29-34 35-36 37-44 45 46-51 PHYSICS
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Year 11 Module 1 – The Chemical Earth The Earth is made up of a large number of different substances: elements‚ compounds & mixtures We can classify elements & compounds as pure substances. These are always HOMOGENEOUS. Mixtures are not pure substances and can be either homogeneous or HETEROGENEOUS. Pure substances have a fixed composition eg copper metal‚ sulfur‚ carbon dioxide (CO2)‚ methane (CH4). Mixtures have variable composition and can also be separated into its components relatively
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UNIVERSITY OF CAMBRIDGE INTERNATIONAL EXAMINATIONS General Certificate of Education Advanced Subsidiary Level and Advanced Level CHEMISTRY Paper 1 Multiple Choice Additional Materials: Multiple Choice Answer Sheet Soft clean eraser Soft pencil (type B or HB is recommended) Data Booklet 9701/11 May/June 2012 1 hour *6083199800* READ THESE INSTRUCTIONS FIRST Write in soft pencil. Do not use staples‚ paper clips‚ highlighters‚ glue or correction fluid. Write your name‚ Centre number and
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that comes with your kit. 2. Draw a sketch of the CH4 model once constructed. 3. Repeat steps 1 and 2 for H2O‚ H3O+ ‚ HCl‚ NH3‚ Cl2‚ N2‚ PCl3‚ CH3OH‚ and CO2. Data: Molecular Formula Un-bonded Pairs on Central Atom Molecular Geometry Polarity CH4 2 Tetrahedral Non-Polar H2O 2 Bent Polar H3O+ 1 Trigonal Pyramidal Polar HC1 0 Linear Polar NH3 1 Trigonal Pyramidal Polar Cl2 0 Trigonal Bi-Pyramidal Non-Polar N2 1 Bent Non-Polar PCl3 1 Trigonal Pyramidal
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purpose of this lab is to write electron configurations‚ orbital filling diagrams‚ and electron- dot diagram for ten elements. Hypothesis: If the amount of electron is know them the configuration of the element is know. Equipment: Paper‚ Pencils Procedure: (IV) Independent Variable - Configuration of electron (DV) Dependent Variable – Multiple Energy Level (CM) Control Method – S‚P‚D‚F Orbital (CMI/C)Constant - S‚P‚D‚F Orbital 1. Prepare a table for this exercise as directed in
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