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    CHEM 2070 LAB

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    Purposes of Experiment: To synthesize a transition metal complex‚ potassium tris (oxalate)ferrate(III) trihydrate in a two step process‚ to learn new laboratory techniques such as decantation‚ recrystallization‚ gravity and suction filtration. Also the purpose of the experiment is to determine the actual‚ theoretical‚ and percent yields of product‚ and characterize the final compound by determining the number of waters of hydration by gravimetric analysis List of Observations: After adding

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    Calorimetry Lab Report

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    First hand investigation of the Dissolution of Solutes Background Information Molar heat of solution * The molar heat of solution of a substance is the heat absorbed when one mole of the substance dissolves in a large excess of water. It is expressed in kJ/mol. * The specific heat of water is a constant‚ with a value of 4.18 J/ g*oC. AIM: To determine the molar heat of solution for two different solids Equipment: * A calorimeter (made using 2 Styrofoam cups with a cardboard lid)

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    Cucumbers Lab Report

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    In this experiment‚ the scientists will research and test which of the four substances is the most efficient at absorbing water in cucumbers. The independent variable is the different substances being used. The dependent variable in the experiment is the amount of water absorbed. There are many constants including the same brand of cucumber slices‚ the same amount of each substance applied‚ the same measuring tools being used‚ and the same observation time. The control of these scientists’ experiment

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    Column Chromatography Lab

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    In paper chromatography‚ some compounds in a mixture travel almost as far as the solvent does; some stay much closer to the base line. The distance travelled relative to the solvent is a constant for a particular compound as long as you keep everything else constant. Some compounds may travel farther than others because they may be composed of more components‚ thus traveling farther. For example‚ black is composed of every color of the rainbow‚ while yellow is composed of less colors. As a result

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    2.2 Immunoprecipitation Different protocols were compared so as to choose the one which is compatible with the characteristics of the particular protein of interest [29]. A suitable amount of nuclear extracts was diluted with 100 microliters of chilled PBS‚ 0.1% Triton 100 (to this mixture‚ the following was added to make a final concentration of 1:1000: 0.2 mM PMSF‚ 0.5 mM DTT and 15 (microgram/ microliter). It was made sure that the final concentration of nuclear extract was 0.5-1.0(microgram/

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    The separation scheme was created by centrifuging a controlled sample of one of the ions or anions combined with one of the reagents such as NaCl. It was found that it could be separated out after centrifuging and would result in a sample without the ions or anions if it precipitated. With the data from week one a method of adding the reagents in a certain order would result in the ability to separate all ions or anions out of a solution. Overall‚ knowing how the cations or anions reacted with certain

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    Redox Area Lab Report

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    Slightly Soluble Y Y Insoluble Y Y Trial Number Total (g) of Zn Total Water Displacement(mL) 1 10.01 1.9 2 20.02 3 3 30.03 4.8 4 40.04 6 Focus Questions 1. The appearance and solubility compares well with the information presented from the CRC Handbook. Our test results shows that

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    Scheme of Analysis for Lab 2 Unknown Sample Description Phase‚ color‚ odor‚ crystalline or gel-like? If crystalline‚ what is crystal shape – needle-like or powdery? Does it look like a pure substance or a mixture? How many components appear to be present? Tests on original sample Flame Test Bushy yellow‚ orange flame – Na+ is present and possibly K+ and NH4+. Pink-purple flame – K+ is present and Na+ is not. (Possibly NH4+) No color or faint trace Na+ - NH4+ is possible‚ K+ and Na+ are

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    Title: Recrystallization of Pure Phthalic Acid‚ Naphthalene‚ and Anthracene Introduction Recrystallization is a method used for purifying solid organic compounds. It is the most efficient method to purify and remove impurities from a solid to allow a crystal to grow. The method is when the solute in a hot solvent yields to a solution. Once the solvent cools‚ the solution is saturated with respect to the solute‚ which is when it recrystallizes. A crystal is the end result of the method and it is a

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    Step 1: Pb (NO3) 2 (aq) + CaCl2 (aq)  PbCl2 (aq) + Ca (NO3) 2 (aq) (double displacement reaction) According to the solubility guidelines lead (II) chloride (PbCl2) is a possible precipitate. This is because even though most chlorides are soluble‚ lead chloride is considered insoluble (p.2‚ Lesson 17). Step 2: PbCl2 ↔ Pb2+ + 2Cl- Q = [Pb2+] [Cl-] 2 Step 3: Ksp = 1.2 x 10-5 (from table 17.1‚ p.5) Step 4: V2 = 20.0 mL (volume of Pb (NO3)2) + 45.0 mL (volume of CaCl2) = 65.0

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