SECTION 2 SECTION REVIEW 1. Marissa’s car accelerates uniformly at a rate of +2.60 m/s2. How long does it take for Marissa’s car to accelerate from a speed of 24.6 m/s to a speed of 26.8 m/s? 2. A bowling ball with a negative initial velocity slows down as it rolls down the lane toward the pins. Is the bowling ball’s acceleration positive or negative as it rolls toward the pins? 3. Nathan accelerates his skateboard uniformly along a straight path from rest to 12.5 m/s in 2.5 s. a. What is Nathan’s
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Motion in 2D Simulation Go to HYPERLINK "http://phet.colorado.edu/simulations/sims.php?sim=Motion_in_2D" http://phet.colorado.edu/simulations/sims.php?sim=Motion_in_2D and click on Run Now. 1) Once the simulation opens‚ click on ‘Show Both’ for Velocity and Acceleration at the top of the page. Now click and drag the red ball around the screen. Make 3 observations about the blue and green arrows (also called vectors) as you drag the ball around. When the ball is stopped there isn’t any changes
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s | vi = 0 m/s | | Find:d = ?? | d = VI*t + 0.5*a*t2 d = (0 m/s)*(32.8 s) + 0.5*(3.20 m/s2)*(32.8 s)2 d = 1720 m ------------------------------------------------- Equations and Problem-Solving * A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car. ------------------------------------------------- Solutions Given: d = 110 m | t = 5.21 s | vi = 0 m/s | | Find:a =?? | d = VI*t + 0.5*a*t2 110 m
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exerted on an object by the expulsion or acceleration of mass in one direction Uniform Circular Motion Uniform Circular Motion is the circular motion with a uniform orbital speed Centripetal Force Centripetal force is the force that acts to maintain circular motion and is directed towards the centre of the circle Centripetal Acceleration Centripetal Acceleration is always present in uniform circular motion it is associated with centripetal force and is also directed at the centre of the circle Period
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constant‚ k = 1.38 × 10 –23 J K –1 gravitational constant‚ G = 6.67 × 10 –11 N m 2 kg –2 acceleration of free fall‚ g = 9.81 m s –2 © UCLES 2006 9702/02/M/J/06 3 Formulae uniformly accelerated motion‚ s = ut + at 2 v 2 = u 2 + 2as work done on/by a gas‚ W = p ⌬V gravitational potential‚ φ = – Gm simple harmonic motion‚ a =– velocity of particle in s.h.m.‚ v = v0 cos t v = ± √(x 20 – x 2)
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go take a look at the first one. As you just saw in this Polo segment‚ Newton’s first law is one of the reason this game exists‚ if you hit the ball with the polo sick the reason for the ball to continue in motion is because of Newton’s First Law‚ “An object in motion will remain in motion unless an external force acts upon it.” But the reasons behind the ball slowing down is because of the outside forces‚ those are acting on the ball‚ causing the ball to slow down. Let’s go take a look at the
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electrical and mechanical efficiency e of the system. Page 1 of 2 ed. Problem statement: We are given the masses of two cylinders‚ one bigger than the other‚ an velocity for the bigger one (as shown)‚ and a motor which powers the motion of the system as shown. The motion is generated by a given electrical input. We are to utilize the given information to find the combined electrical and mechanical efficiency of this system. 100 kg 300 kg Objective: A B 3/119 A Find the combined efficiency in
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Science Term 1 – Rubber Band Racer – Liam Gist A rubber band racer consists of a corflute base‚ a rear axle with rubber wheels and a front axle with plastic wheels. It is powered by a rubber band that can be wound around the rear axle and when released it propels the racer forwards. When the rubber band is wound around the axle it has elastic potential energy and when this energy is release it is transformed into kinetic energy that rotates the rear axle and wheels propelling the car forwards. As
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the ride which are most responsible for these sensations of weightlessness and heaviness are the clothoid loops. The explanation for the various sensations experienced on a roller coaster loop are associated with Newton’s laws of motion and the physics of circular motion.
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c. How far down is the water surface? 4. Aunt Minnie didn’t get her wish‚ so she goes to a deeper wishing well and throws a penny straight down into it at 10 m/s. How far does this penny go in 3 seconds? 75 m CONCEPTUAL PHYSICS Chapter 4 Linear Motion 13 Straight Up and Down The sketch is similar to Figure 4.9 in the textbook. Assume negligible air resistance and g = 10 m/s2. • Table 1 shows the velocity data of the figure for t = 0 to t = 8 seconds. Complete the table. Distances traveled are
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