Animation: Cells & Chemistry Glycolysis After viewing the animation‚ answer these questions. 1. Cells derive energy from the oxydation of nutrients‚ such as glucose . 2. The oxidation of glucose to pyruvate occurs through a series of steps called glycolsis . 3. How many carbons are in a molecule of glucose? 6 4. The energy related during these oxydation reactions is used to form adenosine triphosphate (
Free Diffusion Molecular diffusion Sodium
rate of diffusion. The temperature of the solutions and the difference in concentration of the ion or molecule between the sides of the membrane 2. Why do you think the urea was not able to diffuse through the 20 MWCO membrane? How well did the results compare with your prediction? Since the chemical formula for urea is (NH2)2CO and its molecular weight is about 60. It will not diffuse through the 20 MWCO membrane because it does not ionize. 3. Describe the results of the attempts to diffuse
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Chapter 25 Control of Body Temperature and Water Balance PowerPoint Lectures for Biology: Concepts & Connections‚ Sixth Edition Campbell‚ Reece‚ Taylor‚ Simon‚ and Dickey Lecture by Edward J. Zalisko Copyright © 2009 Pearson Education‚ Inc. Introduction: Chilling Out Bears sleep a lot during winter But bears do not hibernate Instead‚ they become dormant – Body temperature drops from 37°C to 31–34°C – True hibernators may cool to 30°C Dormant bears – Are easily awakened – True
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INTRODUCTION: URINARY TRACT INFECTION | | What is a urinary tract infection (UTI)? The urinary tract is comprised of the kidneys‚ ureters‚ bladder‚ and urethra. A urinary tract infection (UTI) is an infection caused by pathogenic organisms (for example‚ bacteria‚ fungi‚ or parasites) in any of the structures that comprise the urinary tract. However‚ this is the broad definition of urinary tract infections; many authors prefer to use more specific terms that localize the urinary tract infection
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Ammonia and Its Salts 1. Ammonia‚ NH3 is a very important compound in industry. 2. The main uses of ammonia: a) To manufacture nitrogenous fertilizers such as ammonium sulphate‚ ammonium nitrate and urea b) The liquid form is used as a cooling agent (refrigerant) in refrigerators c) As a raw material for the manufacture of nitric acid in the Ostwald process d) To be converted into nitric acid used for making explosives e) As an alkali to prevent the coagulation of latex
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The Results from the Gram positive tests indicated that the unknown #4 was Streptococcus pyogenes. All seven tests on the unknown matched S. pyogenes perfectly. The blood agar plate proved the unknown to be β hemolytic‚ meaning the unknown bacteria was capable of complete hemolysis. This test separated the unknown into the β Streptococcus group‚ narrowing the possible bacteria to S. aureus or S. pyogenes. The Catalase test was used to determine if the unknown could break down hydrogen peroxide
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solute concentration doubled to 18.00 the average diffusion rate increased (doubled) to 0.0300. If we were to plug the provided numbers into Fick’s law‚ it would be supported. 2c. The rate of diffusion differs between sodium and Urea because of the molecular mass. Urea has a larger molecular mass (approximately 60 g/mol) compared
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Osmosis The purpose of this lab is to study how membranes of plant and animal cells react when exposed to different solutions. The first experiment involves purple onion skin and the second involves rat blood in various solutions. I needed to understand certain terms before preforming this lab to be able to efficiently explain what is happening to the cells. Diffusion is the tendency of a substance to move down its concentration gradient from a more concentrated to a less concentrated area.
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Autumn White Biology 258-05 November 26‚ 2012 Unknown #19 Enterbacteriaceae Enterobacter aerogenes ABSTRACT The objective of this report was to identify an unknown microorganism through several differential media tests. Over the course of a couple weeks‚ ten tests were performed. First‚ a gram stain was performed‚ indicating the bacterium was gram negative. An aerotolerance test determined that the bacterium was a facultative anaerobe. Next‚ a negative result in the
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Mole Fraction Return to Solutions Menu The mole fraction is: moles of target substance divided by total moles involved The symbol for the mole fraction is the lower-case Greek letter chi‚ χ. You will often see it with a subscript: χsolute is an example. Example #1: 0.100 mole of NaCl is dissolved into 100.0 grams of pure H2O. What is the mole fraction of NaCl? Solution: 100.0 g / 18.0 g mol¯1 = 5.56 mol of H2O Add that to the 0.100 mol of NaCl = 5.56 + 0.100 = 5.66 mol total Mole fraction
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