I am one of the chemists assigned to design a cost effective procedure for handling the CARBOSE separation and recovery and hazardous waste disposal. The difficulties were trying to figure out is how we can effectively separate Carbose, sand, and naphthalene? The hypothesis we chose to solve this problem was if we put the mixture into water, alcohol, and mineral spirts, then in each solution one or more substance will not dissolve, will be visible, and also able to separate. According to our data our hypothesis supported the experiment because CARBOSE and sand are soluble in water while naphthalene is not. The CARBOSE, and sand will dissolve in the liquid solvent and the naphthalene will remain in the solid phase. In the other substances methanol and mineral spirit were not soluble in both Carbose and sand. Also in naphthalene mineral spirit was not soluble. …show more content…
First use three separate 10ml test tube, and added 10ml of each substance including water, methanol, and mineral spirt. If the Carbose is something that is water soluble, then water can be added to the mixture and then it can be filtered as the sand is insoluble and will be left behind. Also add 0.20 grams of each mixture including Carbose, naphthalene, and sand to each test tube. Try to stir or shake the substance to dissolve. If that didn’t work to dissolve the mixture we made a filter paper and placed it in a funnel then try to filter it by pouring the sample in. After that this leads us on to the third option of separation which is evaporation. At last we placed our sample test in an Erlenmeyer flask and then placed it on a hot surface with melting point 8.2 ◦c, waited to evaporate then recorded our data. After each test, try to observe if the sample was soluble in any of the