SYLLABUS – ADVANCED PLACEMENT CHEMISTRY Required Texts 1. Chemistry: The Central Science by Brown‚ LeMay and Bursten‚ 10th ed.‚ Pearson Education. Inc.‚ Upper Saddle River‚ NJ‚ 2006‚ ISBN: 0131464892 Includes: Text book‚ Laboratory Manual‚ Student Study Guide‚ AP Test Prep Series‚ Solutions to Practice Problems 2. Barrons AP Chemistry‚ Jespersen‚ Neil D‚ 4th ed.‚ Barron’s Educational Series‚ Inc‚ 250 Wireless Boulevard‚ Hauppauge‚ New York 11788
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I https://www.oppapers.com/join.php#submit . Experiments with Metals and Ions of Metals Introduction Metals are similar in their physical properties in general‚ but they are not identical. Most of the metals are solids; few of them are liquids‚ such as mercury and cesium. Density of metals is not similar also. For example‚ sodium has density of 0.97g/cm3 while lead has density of 11.4g/cm3. Melting point of sodium is 98.0oC while for lead it is 327.6oC. Metals have the capability
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be analyzed using gas chromatography. This experiment was performed to show how a radical hydrogenation reaction works with alkanes. Four isomers were attained and then relative reactivity rate was calculated. 1‚1-dichlorobutane had 2.5% per Hydrogen; 1‚2-dichlorobutane had 10%; 1‚3-dichlorobutane had 23%; and 1‚4-dichlorobutane had 9.34% per Hydrogen. Introduction Alkanes are relatively unreactive. There are only a few types of reactions commonly performed. In this lab‚ halogenation was performed
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The objective of this lab was to prepare n-butyl bromide or n-bromobutane‚ which is derived from an alcohol and an acid. In this case‚ n-butyl alcohol and sulfuric acid were the reagents. There were two methods of distillation that was involved in this experiment. The first was by reflux distillation‚ which is used to speed up a chemical reaction without having the reactants/ products evaporate or explode. Data Table 1 indicates the amount of each reagents that was prepared for the reflux apparatus
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Combustion of Acetylene (ethyne) Rx: Back Why I don’t do acetlyene explosions in our lab.... Combustion of alkanes A quick review.... • Combustion reactions of alkanes consist only of C and H (hydrocarbon) • require O2(g) as a reactant • produce CO2(g) and H2O(g) and a large amount of energy!! Oxygen can be the limiting reagent which can lead to Incomplete combustion. For complete combustion of a hydrocarbon‚ oxygen must be in excess. If there isn’t sufficient oxygen‚ incomplete combustion occurs
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w w ap eP m e tr .X w om .c s er June 2003 INTERNATIONAL GCSE MARKING SCHEME MAXIMUM MARK: 40 SYLLABUS/COMPONENT: 0620/01 CHEMISTRY (Multiple Choice) Page 1 Mark Scheme IGCSE EXAMINATIONS – June 2003 Syllabus 0620 Question Number Key Question Number Key 1 2 3 4 5 C B A D A 21 22 23 24 25 B D A B D 6 7 8 9 10 C A A B C 26 27 28 29 30 B D D D B 11 12 13 14 15 B D C D
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immediately reveals a different arrangement of atoms for these substances. Compounds that have the same molecular formula but different structural formulas are termed isomers. In this lab exercise‚ you will determine the different isomers for various alkane
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Epoxidation Reactions Lab Report 2 Abstract An oxygen atom is transferred from a peroxy acid to the carbon=carbon double bond thus forming an epoxide. Scheme 1. Oxone Epoxidation. Scheme 2. mCPBA Epoxidation. The percent yield for the Oxone epoxidation reaction was 65% yield and the mCPBA epoxidation reaction was 70% yield. Oxone is the greener alternative because using mCPBA is twice as expensive as Oxone and leaves behind the epoxide plus m-chlorobenzoic acid while Oxone creates non-toxic
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Write your name here Surname Other names Centre Number Candidate Number Edexcel IGCSE Chemistry Unit: 4CH0 Science (Double Award) 4SC0 Paper: 1C Wednesday 25 May 2011 – Morning Time: 2 hours Paper Reference 4CH0/1C 4SC0/1C You must have: Ruler Candidates may use a calculator. Total Marks Instructions black ink or • Usein the boxesball-point pen. page with your name‚ Fill at the top of this • centre number and candidate number. all • Answer
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IUPAC rules that: (1) Name the longest carbon chain bearing the –OH group. Drop the last –e from the alkane name and add –ol to obtain the root name. (2) Number the longest chain starting at the end nearest the –OH group‚ and designate a number for the –OH group. (Hydroxyl has greater priority than carbon-carbon multiple bonds). (3) Name the remaining substituents and their numbers as for alkanes and alkenes. CH3 OH H3C CH2-Cl CH3 H 1-chloro-3‚3-dimethyl-2-butanol Ch10 Alcohols (Str
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