chains and branches. Carbon Rings: Cyclic Molecules‚ Aromatic Compounds Types of Organic reactions: Combustion Addition Substitution Condensation Oxidation What is organic chemistry? Carbon compounds. Methane CH4 Hexane C6 H14 Ethane C2H 6 Heptane C7 H16 Propane C3H 8 Octane C8 H18 Butane C4H10 Nonane C9H20 Pentane C 5 H12 Decane C1 0 H22 Alkanes: Saturated Hydrocarbons Rules: Cycloalkanes: Alkenes: Alkynes: General formula: Cn H2n General formula: Cn H2n General
Premium Atom Alcohol Chemical reaction
L-6 MCQ (A) MCQs of the Textual Exercise 1) In haloalkane _________ bond is formed between carbon and halogen. (a) Ionic (b) van der Waals (c) Covalent (d) hydrogen 2) In haloarene compounds‚ halogen combines with carbon having which hybridization? (a) sp2 (b) sp3 (c) sp (d)dsp2 3) In haloalkane‚ carbon in C-X bond possesses which partial electric charge? (a) Charge less (b) positive (c) negative (d) anionic 4) Which of the following bonds is the strongest?
Premium Alkene Chlorine Methane
COMPARATIVE INVESTIGATION OF ORGANIC COMPOUNDS Abstract Organic compunds were examined to a comparative investigation to differentiate the properties of each sample. The physical state at room temperature‚ odor and color of the sample were noted by simple observation. In terms of solubility in H2O‚ 5% NaOH solution and 5% HCl solution‚ the samples were classified as to miscible‚ slightly immiscible or immiscible for liquid; and very soluble‚ soluble‚ partially soluble or insolubse for solid. The
Premium Benzene Hydrocarbon Carbon
Developing Fuels * All gases take up the same volume under the same conditions. AT room temperature and room pressure this volume is 24 dm3. * Number of moles= volume in dm3 24 * Balanced equations can also be used to work out gas volumes. In the equations: 2Na + 2H2O 2NaOH + H2‚ where 15g of sodium is reacted‚ you can work out the volume of gas from working out the number of moles in 15g Na = 0.65 mol. Then you see that 2 mol of Na 1mol of H2‚ Thus 0.65 mol Na 0.325 mol H2. 0.325
Premium
DETAILED LESSON PLAN IN ADVANCED CHEMISTRY IV- Euler LEARNING OBJECTIVES At the end of the lesson‚ students are expected to: Write the IUPAC name of certain alcohol compounds; SUBJECT MATTER Topic: Nomenclature of Carboxylic Acid References: General‚ Organic and Biochemistry by Denniston‚ Topping and Caret. Page 283-289. Fundamentals of General‚ Organic and Biochemistry by John R. Holum. Page 418-425. Materials: Ball and stick model of compounds Overhead projector Textbooks Pictures of certain
Premium Alcohol Functional group Carbon
Analysis of Alcohols‚ Aldehydes and Ketones Karl Wayne Mancao‚ Raphaell Mordeno‚ Andres Pastrana III*‚ and Shannen Peñaverde Department of Biology‚ University of Santo Tomas‚ Manila‚ Philippines Abstract The proponents have done several tests for identifying alcohols‚ aldehydes and ketones. These tests are Dichromate test‚ Tollens test‚ Lucas test‚ DNPH test and Iodoform test. Three samples got positive result in dichromate test and one in Tollens test. Lucas test got one sample that has
Premium Alcohol Oxygen Aldehyde
drops of phenol soln in test tube + 1 drop FeCl3 soln Aliphatic and Aromatic Hydrocarbons/ Alkenes Bromination in Light (Free Radical Bromination) (Reacts with alkanes) Reagent: Br2 in H2O Observation: decolorization‚ brown ( colorless Procedure: 2 drops of test compound in test tube+ 1 drop 0.05 M Br2 in H2O‚ shake well‚ record observations Bromination in Dark (Electrophilic Addition Halogenation) (Reacts with alkenes) Reagent: Br2 in H2O Observation: decolorization‚ brown ( colorless
Premium Carboxylic acid Alcohol Amine
METHOD | OBSERVATIONS | TEST CHEMISTRY and comments | ALKENE or alkyne i.e. any non-aromatic unsaturated hydrocarbon with a double or triple carbon-carbon bond. | Bubble gas through‚ or add liquid to‚ a solution of bromine in hexane or water. | The orange/brown bromine rapidly decolourises‚ as a saturated colourless organic bromo-compound is formed. | R2C=CR2 + Br2 ==> BrR2C-CR2BrRCCR + 2Br2 ==> Br2RC-CRBr2R = H‚ alkyl or arylSaturated alkanes give no fast reaction with bromine. | Hydroxy group
Premium Carboxylic acid Hydrochloric acid Amine
Title: Experiment 28: Nitration of Methyl Benzoate Objective: The students will learn to nitrate methyl benzoate through electrophilic aromatic substitution reaction. They will learn the importance of regiochemistry in chemical reactions. They might experience disubstitution through a high temperature. Reactions: Observation: The crystals started to form when added 2 g of crushed ice. The addition of hot methanol dissociated the crystals. The crystals reappeared when cooled down in
Premium Benzene Sulfuric acid Stoichiometry
(R) or (S). 7. Give the stereochemical relationships (same compound‚ structural isomers‚ distereomers‚ or enantiomers) between each pair of isomers. 8. Consider the following free radical bromination of an enantiomerically pure alkane. Is the product formed as a single enantiomer or a racemic mixture? Is the product optically active or optically inactive? Explain your answers. Substitution and elimination reactions (Chpt 11): 9. Predict the products of the following
Premium