10-4‚ 10-4‚ 5x 10-5‚ and 10-5 molar concentrations of Calcium Chloride. ( 10-2 are provided ). By using this formula‚ we can get the amount of calcium chloride to be added in making 50 ml suspensions containing 5% w/v of sulpharmerazine. M1V1 = M2V2 M2 = 5 x 10-3‚ 10-3‚ 5 x 10-4‚ 10-4‚ 5x 10-5‚ and 10-5 M ‚ V2 = 50ml M1 = 0.01M Thus‚ V1 = ( M2 . V2 ) / M1 For‚ i) 5 x 10-3 molar concentrations‚ iv) 10-4 molar concentrations‚ V2 = ( 5 x 10-3 x 50 ) / (0.01)
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the Osmolarity of a Potato Mishal Hasan Abstract Students in Biology find it difficult to understand the concept of tonicity and osmolarity in a real time situation. In this investigation‚ several concentrations of sucrose were used to determine the osmolarity of a potato. It was found that the concentration of sucrose was close to 3.6 in the potato used showing that it was isotonic. Anything above caused the potato to gain weight showing that it was a hypotonic solution and anything below caused the
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Investigation: 20 How much cobalt is in the soil? Introduction: By completion of investigation 20‚ a standard curve of absorbance versus known cobalt (II) nitrate was prepared. The concentration of cobalt (II) ion obtained from a soil sample was determined. Whether or not cobalt nitrate should be added to the soil was determined. If cobalt nitrate needs to be added‚ then how much will it be required to meet the necessary nutritional needs of the animals was established. In colorimetry
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AP Biology August 23‚ 2012 Egg Osmosis Lab Definition of osmosis: The diffusion of water across a selectively permeable membrane from high to low concentrations Hypothesis: If I place an egg in vinegar‚ then the outer layer of the egg is going to become slimy and look like rubber. It will also become larger and bubbles will form on and around the egg. Hypothesis: If I place an egg in corn syrup‚ then the egg will become small and the outer layer will not look like rubber any longer. Day one:
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plasmolysis of onion cells (Allium cepa) using NaCl (Sodium Chloride) concentrations of 0.1M‚ 0.2M‚ 0.3M‚ 0.4M‚ 0.5M‚ 0.6M Design Research Question (Aim): The aim of this lab was to determine the point of incipient plasmolysis of onion (Allium cepa) cells using Sodium Chloride (NaCl) concentrations of 0.1M‚ 0.2M‚ 0.3M‚ 0.4M‚ 0.5M‚ 0.6M. Hypothesis: When the water concentration of a solution outside the cell is lower than the concentration inside the cell‚ water will move from the inside to the outside
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occurred because of the levels of concentration of solute in the different solutions. Since the 4 M solution had the highest concentration of solute‚ compared to the other three solutions tested‚ and a higher concentration of solute than that of the solution inside the egg‚ it was a hypertonic solution.
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From the results obtained and the bar graph plotted‚ it could be seen that when there was a high concentration of sugar the mass of beetroot decreased. This happened because water moved from the inside of the beetroot‚ where there was a high water potential into the sugar solution‚ which had a lower water potential. In the other four beakers where the concentration of sugar solution was less‚ the mass of the beetroot increased. This happened because water moved from the dilute sugar solution where
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environment have equal concentrations of solutes. Therefore cells in an isotonic solution do not experience osmosis. When the cell is hypotonic it has a lower concentration of solutes so water will move out of the cell. When the cell is hypertonic‚ it will have a higher concentration of solutes and water will move into the cell to attempt to reach an isotonic state. The primary purpose of this exercise is to measure the rate and direction of osmosis under different concentrations. The greater the
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level off‚ the results were recorded as the freezing point of pure water. The value was recorded in a lab notebook. For part 2 of the experiment‚ the van’t Hoff Factor of sodium nitrate was determined. 25mL of sodium nitrate was obtained and the concentration information recorded. A large test tube was filled 1/3 full of the solution and placed into the ice bath. The probe was placed in the test tube and the “collect” button pressed. The solution was stirred and once the temperature leveled off‚ the
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area of least concentrated‚ which is equal to moving down a concentration gradient. When the molecules have reached equal concentrations in both locations‚ diffusion ends and it has reached equilibrium. Molecules continue to move‚ but move in both directions equally; there is no net change! Osmosis is the movement of water. It moves water molecules across a cell membrane either in or out of the cell and still moves down the concentration gradient. The object is still to reach equilibrium. Osmotic
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