©TutorBreeze.com Please do not copy the answer given here Write to us for help in understanding the solution NCERT/CBSE CHEMISTRY CLASS 12 textbook http://www.TutorBreeze.com Contact for Online Tutoring in Physics‚ Math‚ Chemistry‚ English (v) Benzene to 4-bromonitrobenzene :- (vi) Benzyl alcohol to 2-phenylethanoic acid :- (vii) Ethanol to propanenitrile :- (viii) Aniline to chlorobenzene :- (ix) 2-Chlorobutane to 3‚ 4-dimethylhexane:- ©TutorBreeze.com Please do not copy the answer
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routes is reviewed. Production of KA oil from phenol is also covered‚ as is the Asahi process for cyclohexanol production from benzene via cyclohexene. Appropriately adjusted nitric acid oxidation is appended to each of these processes. Solutia‚ working with the Boreskov Institute of Catalysis (BIC) in Russia‚ has developed a one step process to manufacture phenol from benzene‚ using nitrous oxide for the oxidation step. Thus‚ by coupling phenol production and adipic acid production‚ Solutia has
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and tri- substitution. Meta directors don’t have that unshared electron pair that is used to push an atom closer to the benzene ring. In our reaction above the substitution would be more di-substitution favored. The positive charges are further away from each other in the benzene ring. Most if not all meta directors have a group with-full positive charges next to the benzene ring. If perhaps you were to be given different results maybe their would be an increase in temperature that would result
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determine the structure of the major component of star anise oil. It is already known that this component has a molecular formula C10H12O. This molecular formula equates to an IHD of 5. It is evident‚ by calculating the IHD‚ that this compound contains a benzene ring. By heating anisene with hydroiodic acid the following reaction occurs: [rxn 1] The resultant of a phenol indicates that anisene is‚ in fact‚ an aryl methyl ether with the formula C9H9OCH3. Since all these facts have been established about the
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Nicole Vigliotti Partner: Camille Dupiton Lab #1 Purification of a Solid: Crystallization and Melting Point Section: A61 Laboratory Exercise #1 Purification of a Solid: Crystallization and Melting Point Introduction In this lab exercise‚ we will be learning experimental techniques using glassware and other apparatuses. In order to successfully complete this lab‚ we will use techniques 1.0‚ 1.1‚1.2‚2.0‚2.1‚2.2‚ and 2.3 that are described in the Lab Manuel.
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fractions: H2O ⇒ 1.34 mol / (1.34 mol + 0.543 mol) = 0.71 C2H5OH ⇒ 0.543 mol / (1.34 mol + 0.543 mol) = 0.29 Example #3: A solution contains 10.0 g pentane‚ 10.0 g hexane and 10.0 g benzene. What is the mole fraction of hexane? Solution: 1) You need to determine the moles of pentane‚ hexane and benzene: to do this‚ you need the molecular weights. Here are the formulas: pentane: C5H12
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around 1900 cm-1 indicates the presence of a benzene ring. For the product‚ the peaks located just over 3000 cm-1 indicate carbon hydrogen bonds. The weak carbon-carbon double bond peak located at 1621 cm-1 indicates the presence of a trans alkene. This is also supported by the peak located at 964.93 cm-1‚ the trans isomer peak. The two peaks at 1621.31 and 1516.29 cm-1 along with the overtones located around 1900 cm-1 indicates the presence of a benzene ring. Based on this data‚ it can be concluded
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Additional Questions: 1. H H H C C H H C C H C H H C H H Compound A Compound A is an intermediate compound found in a production plant attempting to synthesise n-hexane. a) List three physical properties of alkynes. b) Give the IUPAC name of compound A. [3 marks] [2 marks] c) There are several ways to form the final product from Compound A. An operator has decided to use Pt catalyst to react with Compound A. Write the complete chemical reaction equation. [3 marks] d) The quality assurance
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rhamnolipid biosurfactants on the first-order biodegradation rate constant for a microbial consortium growing on a mixture of hydrocarbons representing four structural classes of hydrocarbons. The microbial biodegradation rate of hexadecane‚ dodecane‚ benzene‚ toluene‚ iso-octane‚ pristane (2‚6‚10‚14 tetramethyl pentadecane)‚ naphthalene‚ and phenanthrene in the presence and absence of a mixture of rhamnolipid biosurfactant was determined. A first-order biodegradation model was applied in these studies
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can‚ because one quantum of UV light has sufficient energy (396 kJmol-1) to break the typical covalent bond (with BE of about 300 kJmol-1) while the other two do not. | Platinum Catalyst; Reforming of straight chain Alkanes | Used as catalyst. Benzene can be formed from the reforming of hexane. | Aqueous Br2 vs. Br2/NaCl; Electrophilic Addition reaction btw Halogens and Alkenes | Aq Br2 bromoalcohol formed: Br- & OH- are present in solution when carbocation is formed.Br2/NaCl bromochloro
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