No. Wavelength cm -1 Interpretation 1 3500-3400 cm -1 O-H hydroxyl group 2 2900-2850 cm -1 C-H alkanes group 3 1150-1100 cm -1 C-O alcohol‚ ether group FTIR of HPMC Table 9.11: FTIR interpretation analysis of HPMC S. No. Wavelength cm -1 Interpretation 1 3600-3500 cm -1 O-H phenols group 2 2950-2850 cm -1 C-H Alkenes group 3 1400-1300 cm -1 Methyl bonding FTIR analysis of Pantoprazole + HPMC Table 9.12: FTIR interpretation analysis of Pantoprazole
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The E2 reaction performed began by dehydrohalogenating the 3-chloro-3‚ 7-dimethyloctane with potassium hydroxide in aqueous ethanol. The 3-chloro-3‚ 7-dimethyloctane will lose a hydrogen from three different carbons that cause the formation of three constitutional isomers. If the hydroxide ion attacks a hydrogen on the 3-methyl carbon‚ then 2-ethyl-6-methyl-1-heptene will be the product. If a hydrogen on the carbon-2 was attacked‚ then the product would be 3‚ 7-dimethyl-2-octene. If a hydrogen was
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IGCSE PRE-AICE CHEMISTRY 0620 OFFICIAL STUDY GUIDE Notes: To avoid any confusion concerning the symbol for litre‚ dm3 will be used in place of l or litre.Valence electrons are known as valency electrons for this test. Nature of Matter The states of matter are solid‚ liquid‚ and gas‚ in respective order of kinetic energy. State of Matter | Definite Volume | Definite Shape | Solid | Yes | Yes | Liquid | Yes | No | Gas | No | No | Diffusion:
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Fluid Catalytic Cracking Fluid catalytic cracking* (FCC) is the most important conversion process used in petroleum refineries. It is widely used to convert the high-boiling hydrocarbonfractions of petroleum crude oils into more valuable [1][2][3] gasoline‚ olefinic gases and other products. . Cracking of petroleum hydrocarbons for conversion of heavy fractions into lighter fractions was originally done by thermal cracking which has been almost completely replaced by catalytic cracking because
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and Applied Chemistry (IUPAC) General Form of IUPAC Nomenclature [branching substituent(s)] Root [Suffix] Rules: 1. Identify the longest continuous chain of carbon atoms. This chain determines the parent name (root) of the alkane. The parent suffix for alkanes is‚ not surprisingly‚ -ane. For chains of equal length‚ pick the one with the most substituents. (Note: I number all possibilities going from left to right – identify the longest chain) 2. Number the chain beginning at the
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Introduction to Alkane Nomenclature A. Determining the Priority of Functional Groups. What’s in a name? 3-ethyl-5-(1-methylpropyl)-4‚4-dimethylnonane Too big a subject to cover on one sheet! This paper will focus on alkanes. Determining functional group priority will be the subject of a subsequent sheet. suffix http://masterorganicchemistry.com D. Applying the Lowest Locator Rule F. Dealing With Branched Substituents (the IUPAC Way) Number the chain from one end so as
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and conjugation – theory of resonance‚ structure of alkenes‚ allyl‚ vinyl systems. 4) Acidity‚ basicity and pKa 5) Conformational Analysis - Cyclohexane 6) Stereochemistry – regioselective‚ stereoselective‚ stereospecific 5 Examples of Topics covered for Revision Quiz 1 (not limited to the topics below) 1) 2) 3) 4) 5) 6) 7) 8) Acids and Bases Conformations of Alkanes and Cycloalkanes Alcohols and Alkyl halides Elimination Reactions of Alkenes SN1 and SN2 Aromaticity and Electrophilic Aromatic
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dipole. 6 Structure and Properties of Alcohols •Alcohols have an H atom bonded to an O atom‚ making them capable of intermolecular hydrogen bonding. •All of these properties give alcohols much stronger intermolecular forces than alkanes and alkenes. 7 Structure and Properties of Alcohols •Therefore‚ alcohols have higher boiling and melting points than hydrocarbons of comparable size and shape. stronger intermolecular forces higher boiling and melting point 8 Structure and
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Comparison of the rate of reaction and yield of glycerol in saponification with different triglycerides Chemistry EE Candidate number: 0019 Word count: 3974 TABLE OF CONTENTS CONTENTS 2 INTRODUCTION 2 RESEARCH QUESTION 5 BACKGROUND INFORMATION 5 METHODOLOGY 10 DATA PRESENTATION AND PROCESSING 13 CONCLUSION 24 EVALUATION 24 BIBLIOGRAPHY 26 Introduction In 1779‚ Carl W. Scheele‚ a Swedish chemist‚ discovered a new transparent‚ syrupy liquid by heating olive oil and litharge . This
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to the number of the C atoms attached to it. Nomenclature of haloalkanes Haloalkanes are named by adding prefix fluoro‚ chloro‚ bromo or iodo to the name of the corresponding alkanes. Physical properties of haloalkanes Haloalkanes have stronger intermolecules force compared to alkanes and alkenes. Melting and Boiling Points Name Formula Physical State Melting Point/°C Boiling Point/°C Fluoromethane CH3F Gas -142 -78 Chloromethane CH3Cl Gas -97 -24 Bromomethane CH3Br
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